This text is displayed if your browser does not support HTML5 Canvas. Var flip = document.getElementById('flip')
#Java mouse coordinates offset code#
second, how can i write a code that works for ie, firefox, chrome, safari and opera? I have two questions, first, what is the right thing to do to get the correct mouse position under firefox. but it seems that layerX is the position of my mouse relative to the web page, not the position of the canvas. This works very well in chrome, however when it comes to firefox, it doesn't work. Right now, I am using x=event.offsetX to get the mouse position. My code is simple, but I have a problem getting the mouse cursor position within the canvas. When the mouse move, I draw red squares under my mouse. All I want to do is a simple html5 drawing example.
Your painting logic assumes you always drag the mouse from top/left to bottom/right. Import ĮventQueue.I'm studying jquery and html5 canvas. 2 Answers Sorted by: 4 myRectangle new Rectangle2D.Double (StartX, StartY, myX2, myY2) The parameters are (x, y, width, height) you are trying to specify two points.
You would then be in a position to better ascertain the location of the image and convert the mouse point values you require, for example. So, the task is to find the coordinates of the mouse over the screen.
This means that vertical zero is topmost point and horizontal zero is the leftmost point. Instead, you could create a custom component and render the image the way you want. The top left corner of the screen is (0, 0) i,e, X and Y coordinate is (0, 0). While you could create your own delegate, you would end up needing to create one for each supported platform and.I'm too lazy. Place VI Server Reference ( ProgrammingApplication ControlVI Server Reference) and left-click This VI.
#Java mouse coordinates offset how to#
The following steps explain how to calculate it programmatically. How can I modify above code to get coordinates relative to image?īasically, it would be very hard to achieve this using a JLabel as the actual position of the image is determined by the JLabel's look and feel delegate. In order to relate the mouse cursor position to the positions of most front panel objects, you would need the mouse cursor position relative to the pane coordinate system. So here's the problem: the JPanel is larger than the image and the JScrollPane is taking up 100% of the JPanel (which looks nice, I'm happy about that) but the mousePressed event is giving me the coordinates relative to the JScrollPane/JPanel, not the image so the x coordinate is offset (even though the mouseListener was add to the JLabel containing the ImageIcon). Java robot type string - simulate user typing/input. ScreenLabel.addMouseListener(new MouseAdapter() //I override only one method for presentation I need to get the cursor position in other window but pygui is giving the position where am running. ScreenScroll.getViewport().setBackground(Color.white) JScrollPane screenScroll = new JScrollPane(screenLabel) final JLabel screenLabel = new JLabel(new ImageIcon(image)) The JScrollPane, screenScroll, is contained in a JPanel with a BorderLayout. I want to get the mouse coordinates of a mouse click relative to an image which is within a JSrollPane.
I am building a desktop application in Java.
0 kommentar(er)
